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>>82340
Thank you!

Here's today's portion.

1 liter of cola contains 6.2 g of CO2

Mr(CO2) = Ar(C) + 2Ar(O)

Mr(CO2) = 6 + 2 * 16 = 44 g/mol

6.2 g / 44 g/mol = 0.14 mol

For any gas Vm = 22.4 L/mol

V(CO2) = 0.14 mol * 22.4 L/mol = 3.1 L
Post number No.82343
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